Let I -01 e x-1- x dx-01x2 ex-x-1 d x equalsA- 2- IB- I - eC- e -2- ID- 2- e - I

The correct option is D 2 e + I ∫_0^1 x^2 e^x/x+1dx =∫_0^1e^x(x 1)+I=I e+2 ...

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Definite Integrals

Let I =∫01 e ...

Question

Let $I = \int_{0}^{1} \frac{e^{x}}{1 + x} d x$
$\int_{0}^{1} \frac{x^{2} e^{x}}{x + 1} d x$ equals

2 + I

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I - e

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e - 2 + I

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2 - e + I

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Solution

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I

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