Let I -01 e x-1- x dx-34e-x-x-5 equalsA- -I e-4B- I- e 4C- I - e -4D- Ie -4

The correct option is A I e^ 4 Put x+4=t given ∫_3^4e^ xdx/x 5= Ie^ 4 ...

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Integration by Substitution

Let I =∫01 e ...

Question

Let $I = \int_{0}^{1} \frac{e^{x}}{1 + x} d x$
$\int_{3}^{4} \frac{e^{- x}}{x - 5}$ equals

I e^{- 4}

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- I e^{- 4}

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I + e^{4}

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I - e^{- 4}

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Solution

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