wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let I=313+x3dx, then the value of I lies in the interval


A

[4, 6]

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

[1, 3]

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

[4,230]

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

[15,30]

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct options are
A

[4, 6]


C

[4,230]


f(x)=(3+x3) this is increasing function on [1, 3]

least value (m) = f(1) = (3+13)=2 and

greatest value M=f(3)=(3+33)=30

So (31)231(3+x3)dx(31)30

4313+x3 dx230


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Cube Root of a Complex Number
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon