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Question

Let I=313+x3dx, then the value of I lies in the interval


A

[4, 6]

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B

[1, 3]

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C

[4,230]

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D

[15,30]

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Solution

The correct options are
A

[4, 6]


C

[4,230]


f(x)=(3+x3) this is increasing function on [1, 3]

least value (m) = f(1) = (3+13)=2 and

greatest value M=f(3)=(3+33)=30

So (31)231(3+x3)dx(31)30

4313+x3 dx230


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