Let j-1- Then one value of jj is

We know that nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; i=cos π2+i sin π2=e^iπ2 So, nbsp; nbsp; nbsp; nbsp; nbsp; ...

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Complex Function ( Limit, Analytic Function)

Let j=√-1. Th...

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Let $j = \sqrt{- 1}$ . Then one value of $j^{j}$ is

\sqrt{3}

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- 1

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\frac{\sqrt{1}}{2}

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e^{\frac{- π}{2}}

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I_{n} = 1 \int 0 \frac{x^{n}}{x^{2012} - 1} d x, J_{n} = 1 \int 0 \frac{x^{n}}{x^{2013} + 1} d x

n > 2012, n \in N

A = (a_{i j})_{3 \times 3},

a_{i j} = {\begin{matrix} I_{2012 + i} - I_{i}, i = j 0, i \neq j \end{matrix}

B = (b_{i j})_{3 \times 3},

b_{i j} = {\begin{matrix} J_{2016 + j} + J_{j + 3}, i = j 0, i \neq j \end{matrix} .

trace (A^{- 1}) + | B^{- 1} |

i, j, k

[\begin{matrix} i - j & j - k & k - i \end{matrix}] =

\vec{a} = 3 \hat{i} - \hat{j} + 2 \hat{k}

\vec{b} = 2 \hat{i} + \hat{j} - \hat{k},

(\vec{a} \times \vec{b}) \vec{a} .

If \vec{a} = \hat{i} - \hat{j} and \vec{b} = \hat{j} + \hat{k}, then {|\vec{a} \times \vec{b}|}^{2} + {|\vec{a} . \vec{b}|}^{2} =________________.

\vec{a} = 5 \hat{i} - \hat{j} + 7 \hat{k} a n d \vec{b} = \hat{i} - \hat{j} + λ \hat{k} .

\vec{a} + \vec{b}

\vec{a} - \vec{b}

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