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Question

Let k be an integer such that the sum of the digits of k is 4 and 105<k<106. How many values can k have?

A
36
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B
46
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C
45
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D
56
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Solution

The correct option is D 56
Given 105<k<106
k is a 6 digit number whose digits sum =4
Different possibilities for 6 digits sum =4:
1).(4,0,0,0,0,0)=1 way
2).(1,3,0,0,0,0)=2C1×5C1=10 ways
3).(2,2,0,0,0,0)=3C1×5C2=3×10=30 ways
4).(2,1,1,0,0,0)=1×5C3=10 ways
Total =1+10+5+30+10
=56.
Hence, the answer is 56.

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