Let k- x - 0 limxsin xx2- then the value of 5k-1 - k is

k=lim_x→ 0xsin xx^2 k=lim_x → 0sin xx k=1 5k+1k=5(1)+11=6 ...

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Substitution Method to Remove Indeterminate Form

Let k= x →...

Question

Let $k = lim x \to 0 \frac{x sin x}{x^{2}}$ , then the value of $\frac{5 k + 1}{k}$ is

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Solution

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x^{2} + x + 1

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x^{2} + 2 x + 3 k = 0

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