Let L1 be the line r1=2→i+→j−→k+λ(→i+2→k) and L2 be the line r2=3→i+→j+μ(→i+→j−→k). Let π be the plane which contains the L1 and is parallel to L2. The distance of the plane π from the origin is
A
1.7
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B
√2√7
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C
√6
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D
None of these
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Solution
The correct option is B√2√7 Equation of plane containing L1 is given by, a(x−2)+b(y−1)+c(z+1)=0 Now this plane is perpendicular to both the given lines ⇒a+2c=0..(1) and a+b−c=0..(2) Solving (1) and (2), we get a=−2c and b=3c Therefore plane is −2(x−2)+3(y−1)+(z+1)=0 ⇒−2x+3y+z+2=0 Hence, distance of this plane from origin is =∣∣∣222+32+12∣∣∣=√27