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Closure properties of CFL Part - 2

Let L be a co...

Question

Let L be a context-free language and M a regular language. Then the language L $\cap$ M is

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Solution

L is CFL and M is Regular. Intersection of CFL and Regular is always a CFL, since all languages are closed under regular intersection.

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L_{1}

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Q. Let L(R) be the language represented by regular expression R. Let L(G) be the language generated by a context free grammar G. Let L(M) be the language accepted by a Turing machine M.
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