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Closure properties of CFL Part - 2
Let L be a co...
Question
Let L be a context-free language and M a regular language. Then the language L
∩
M is
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Solution
L is CFL and M is Regular. Intersection of CFL and Regular is always a CFL, since all languages are closed under regular intersection.
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Similar questions
Q.
Let
L
1
be a regular language and
L
2
be a context-free language. Which of the following languages is/are context-free?
Q.
Let L(R) be the language represented by regular expression R. Let L(G) be the language generated by a context free grammar G. Let L(M) be the language accepted by a Turing machine M.
Which of the following decision problems are undecidable?
I. Given a regular expression R and a string w,is
ω
ε
L(R)?
II. Given a context-free grammar G, is L(G)=
ϕ
III. Given a context-free grammar G, is L(G) =
∑
∗
for some alphabet
∑
?
IV. Given a Turing machine M and a string
ω
, is
ω
ε
L(M)?
Q.
Which of the following problems are decidable?
1. Does a given program ever produce an output?
2. If L is a context-free language,then, is
¯
L
also context-free?
3. If L is a regular language,then,is
¯
L
also regular
4. If L is a recursive language,then,is
¯
L
also recursive
Q.
A language L satisfies the Pumping Lemma for regular languages, and also the pumping Lemma for context-free languages. Which of the following statements about L is TRUE?
Q.
Let P be a regular language and Q be a context-free language such that
Q
⊆
P
. (For example, let P be the language represented by the regular expression
P
∗
q
∗
and Q be
{
p
n
q
n
∣
n
ϵ
N
}
Then which of the following is ALWAYS regular ?
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