wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let L=limx0aa2x2x2/4x4,a>0.


If L is finite, then?

A
a=2,L=164
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
a=1,L=164
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
a=3,L=132
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
a=1,L=132
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B a=2,L=164
L=limx0aa2x2x2/4x4
Applying L-Hospital's rule, L=limx02xxa2x28x3a2x2
=limx0xa2x2(2a2x21)8x3a2x2
=limx0(2a2x21)8x2
As x0, denominator tends to 0, so the numerator also tends to 0.
limx02a2x21=0
a=2
So, L=limx024x2x2/4x4
Applying L-Hospital's rule, =limx0(24x21)8x2
Again ,applying L-Hospital's rule, =limx02x(4x2)3/216x=164
Hence, option 'A' is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration of Irrational Algebraic Fractions - 1
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon