Let - a- - - b- - - a-b- -1- then the angle between a- and b- is

The correct option is A π3 |a b|=1 ⇒ |a b|^2=1 ⇒ a^2+b^2 2a.b=1 ⇒ 2 2a.b=1 ⇒ 2a.b= 1 ⇒a.b=12 ⇒ |a||b|cosθ=12 ⇒θ=π ...

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Applications of Dot Product

Let | a⃗ |=...

Question

Let $| \to a | = ∣ ∣ \to b ∣ ∣ = ∣ ∣ \to a - \to b ∣ ∣ = 1$ , then the angle between $\to a$ and $\to b$ is

\frac{π}{6}

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\frac{π}{3}

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\frac{π}{4}

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\frac{π}{2}

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