Question

Let line L: $\frac{x-1}{2}=\frac{y-1}{1}=\frac{z-0}{4}$ & Plane P: $x+2y-z=3$
Then which of the following is true?

• A. Line is perpendicular to plane
• B. Line is neither parallel nor perpendicular to plane
• C. Plane contains the line
• D. Line and plane do not intersect

Answer 1

The correct option is C Plane contains the line

Given line L: $\frac{x-1}{2}=\frac{y-1}{1}=\frac{z-0}{4}$

Plane P: $x+2y-z=3$

So from the below option c $i.e.$ plane contains the line is correct