Question

Let ${\log }_{10}p=0.030,{\log }_{10}q=-2.48$ and ${\log }_{10}r=-0.45$ , then the sum of mantissas of $p,q$ and $r$ is

Answer 1

${\log }_{10}p=0.030\Rightarrow m_p=0.030{\log }_{10}q=-2.48=-3+0.52\Rightarrow m_q=0.52{\log }_{10}r=-0.45=-1+0.55\Rightarrow m_r=0.55$

$\therefore m_p+m_q+m_r=0.030+0.52+0.55=1.10$