Question

Let $m_1$ be the slope of the line containing the points $(3,5)$ and $(6,10)$. Let there be another line with slope $m_2$ such that $m_1\times m_2=-1$. Find the equation of the other line.

• A. $x+5y=15$
• B. $3x+5y=15$
• C. $3x+y=5$
• D. $-5x+y=\frac{1}{3}$

Answer 1

The correct option is B $3x+5y=15$

The slope $m_1$ is given by $m_1=\frac{10-5}{6-3}=\frac{5}{3}$.

Hence, $m_2=\frac{-3}{5}$.

Therefore the line with the slope $m_2$ will be of the form $y=m_{2}x+c$.

But $m_2=\frac{-3}{5}$.

Hence, the equation will be of the form $5y=-3x+d$ or $3x+5y=d$