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Question

Let m1 be the slope of the tangent at a point P on the curve y=x3. This tangent at P intersects the curve again at Q. If the slope of tangent at Q is m2 and m2=km1, then the value of k is

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Solution

Let P(x1,y1), Q(x2,y2)
y=x3dydx=3x2m1=3x21 (1)
Equation of tangent at P(x1,y1) is
yy1=3x21(xx1)yx31=3x21(xx1)y3x21x+2x31=0 (2)

Tangent at P intersects the curve again at Q(x2,y2)
So, substituting (x2,x32) in eqn(2), we get
x323x21x2+2x31=0(x2x1)(x22+x1x2+x213x21)=0
x22+x1x22x21=0 (x1x2)
(x2x1)(x2+2x1)=0
x2=2x1 (x1x2)
Now, slope of tangent at Q(x2,y2) is
m2=3x22=3(2x1)2=4(3x21)k=4

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