Let M and m be respectively the absolute maximum and the absolute minimum value of the function, f(x)=2x3−9x2+12x+5 in the interval [0,3]. Then M−m is equal to :
A
5
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B
1
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C
4
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D
9
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Solution
The correct option is D9 f(x)=2x3−9x2+12x+5f′(x)=6x2−18x+12=6(x−1)(x−2)f′(x)=0⇒x=1,2f(0)=5,f(1)=10,f(2)=9,f(3)=14⇒M=14&m=5∴M−m=14−5=9