Let M denotes the mass of earth and let R denotes its radius. The ratio g/G at earth's surface is?

R^{2} / M

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M / R^{2}

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M/R

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R/M

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Solution

The correct option is A $M / R^{2}$
Gravity at the surface of earth $g = \frac{G M}{R^{2}}$
$\frac{g}{G} = \frac{M}{R^{2}}$ .

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Let M denotes the mass of earth and let R denotes its radius. The ratio g/G at earth's surface is?

The correct option is A M/R2Gravity at the surface of earth g=GMR2gG=MR2.

The correct option is A $M / R^{2}$
Gravity at the surface of earth $g = \frac{G M}{R^{2}}$
$\frac{g}{G} = \frac{M}{R^{2}}$ .