wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let P=(1,0,1)Q=(1,2,0)R=(2,0,3)S=(3,2,1), then the length of the component of RS on PQ is

A
1/3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2/3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4/3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
5/3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 4/3
PQ(11,20,0(1));RS(32,20,1(3))
PQ(2,2,1);RS(1,2,2)
|PQ|=3(4+4+1);|RS|=3(1+(2)2+(2)2=9)
cosθ=(2)(1)+(2)(2)+(1)(2)(2)2+(2)2+(1)2(1)2+(2)2+(2)2⎢ ⎢cosθ=a1a2+b1b2+c1c2a21+b21+c21 a22+b22+c22⎥ ⎥
cosθ=49
|RS|cosθ=3×49=43 ( component of RS on PQ is RScosθ)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon