Let v1 be the frequency of the series limit for Lyman series, v2 the frequency of the first line of the Lyman series and v3 the frequency of the series limit of Balmer series. Then which of the following relations is true?
A
v1−v2=v3
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B
v2−v1=v3
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C
v3=v1+v22
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D
v1+v2=v3
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Solution
The correct option is Dv1−v2=v3 Series limit means the shortest possible wavelength (maximum photon energy) and first line means the longest possible wavelength, (minimum photon energy) in the series v=c[1n2−1m2], where c is a constant. For series limit of Lyman series n=1m=∞v1=c For first line of Lyman series n=1m=2v2=3c4 For series limit of Balmer serles n=2m=∞v3=c4 :. v1−v2=v3