Question

Let $z$ be any point in $A\cap B\cap C$. Then, $|z+1-i{|}^2+|z-5-i{|}^2$ lies between

• A. 25 and 29
• B. 30 and 34
• C. 35 and 39
• D. 40 and 44

Answer 1

The correct option is C 35 and 39

The points $(-1,1)$ and $(5,1)$ are the extremities of a diameter of the given circle.
Hence $|z+1-i{|}^2+|z-5-i{|}^2=36$.