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Question

Let a=1,b=2 and c=3 and a,b,c be threee non-coplanar vectors. If d=4, then [dbc]a+[dca]b+[dab]c[abc] is equal to

A
2
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B
4
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C
1
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D
None of these
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Solution

The correct option is C 2
[a+bb+c]{(a+b)×b×c}c+a{a×b+a×c+b×b+b×c}(c+a)a×bc+a×cc+b×bc+b×c+a×ba+a×ca+b×b+b×ca[abc]+0+0+0+0+0+[bca]=2[abc]Ans.

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