Let mixture be prepared by mixing nA moles of liquid A and nB moles of liquid B. Let PA and PB be the partial pressures of two constituents and P∘A and P∘B are the vapour pressures in pure state. Which of the following relations are true?
A
PA=P∘A×ηAηBPB=P∘B×ηBηA
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B
P∘A=PAηAηA+ηBP∘B=PBηBηA+ηB
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C
PA=P∘A×ηAηA+ηBPB=P∘B×ηBηA+ηB
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D
P∘A=PA.nBP∘B=PB.nB
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Solution
The correct option is CPA=P∘A×ηAηA+ηBPB=P∘B×ηBηA+ηB If two volatile liquids of vapor pressures P∘A,P∘B are mixed together to form a solution. The partial pressure of one component is equal to Vapour pressure of pure component multiplied by mole fraction. So putting this definition in the equations PA=P∘A×ηAηA+ηBPB=P∘B×ηBηA+ηB