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Question

Let mixture be prepared by mixing nA moles of liquid A and nB moles of liquid B. Let PA and PB be the partial pressures of two constituents and PA and PB are the vapour pressures in pure state. Which of the following relations are true?

A
PA=PA×ηAηBPB=PB×ηBηA
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B
PA=PAηAηA+ηBPB=PBηBηA+ηB
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C
PA=PA×ηAηA+ηBPB=PB×ηBηA+ηB
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D
PA=PA.nBPB=PB.nB
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Solution

The correct option is C PA=PA×ηAηA+ηBPB=PB×ηBηA+ηB
If two volatile liquids of vapor pressures PA,PB are mixed together to form a solution. The partial pressure of one component is equal to Vapour pressure of pure component multiplied by mole fraction.
So putting this definition in the equations
PA=PA×ηAηA+ηBPB=PB×ηBηA+ηB

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