Let n1,n2,n3....are the frequencies of segments of a stretched string, then the frequency n of the string can be given by
A
n=n1+n2+n3+.....
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B
n=√n1×n2×n3×....
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C
1n=1n1+1n2+1n3+....
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D
None of the above
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Solution
The correct option is C1n=1n1+1n2+1n3+.... We know that for a vibrating string n1l1=n2l1=n3l3....=k(constant)=nl Also, l1+l2+l3+....=1 ∴kn1+kn2+kn3....=kn =1n=1n1+1n2+1n3+......