The correct option is C Number of divisors that are multiple of 3 is 45
Here N=24⋅33⋅52
Total number of divisors
=(4+1)(3+1)(2+1)=60
Now, the number of odd divisors
=(3+1)(2+1)=12
Then the number of even divisors
= total divisors − odd divisors
=60−12=48
For factors to be a multiple of 3, we must select at least one 3 which can be done in 3 ways,
Therefore, the number of divisors that are multiple of 3
=(4+1)×3×(2+1)=45
We know that 15=3×5
For factors to be a multiple of 15, we must select atleast one ′3′ and atleast one ′5′
Therefore, the number of divisors that are multiple of 15
=(4+1)×3×2=30