Question

Let N= $141\times 143$. What is the remainder when N is divided by $3$?

• A. $3$
• B. $0$
• C. $2$
• D. $1$

Answer 1

The correct option is B $0$

Instead of multiplying both the numbers in N, factorise both of them.
On prime factorisation of N we get,
N $=(3\times 47)\times (11\times 13)$
It is clear that $3$ is a multiple of N and is completely divisible by $3$.
So, on dividing N by $3$ we get the remainder $0$.