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Question

Let n>2 be an integer and define a polynomial p(x)=xn+an1xn1+.....+a1x+a0 where a0,a1,.....an1 are integers. Suppose we know that np(x)=(1+x)p(x). If b=p(1), then.

A
B is divisible by 10
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B
B is divisible by 3
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C
B is a power of 2
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D
B is a power of 5
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Solution

The correct option is C B is a power of 2
Consider the differential equation,
np(x)=(1+x)p(x)
ny=(1+x)dydx
ndx1+x=dyy
Now on integrating on both sides
ndy1+x=dyy
nln(1+x)+lnc=lny
where lnc is an arbitrary constant.
y=p(x)=c(1+x)n
Now,substitute x=0
c=a0
Now substitue x=1
Then, b=p(1)=a02n
Therefore,Option C is correct.

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