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Question

Let n be a fixed positive integer. Define a relation R on the set Z of integers by, aRbn|ab. Then R is:

A
reflexive only
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B
symmetric only
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C
transitive only
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D
equivalence
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Solution

The correct option is C equivalence
Reflexive: For any aN, we have aa=0=0×na is divisible by n(a,a)R
Thus (a,a)R for all aZ. So, R is reflexive.
Symmetry: Let (a,b)R. Then,
(a,b)R(ab) is divisible by n.
(ab)=np for some pZ
ba=n(p)
ba is divisible by n
Thus, (a,b)R(b,a)R for all a,bZ
So, R is symmetric on Z.
Transitive: Let a,b,cZ such that (a,b)R and (b,c)R. Then (a,b)R(ab) is divisible by n.
ab=np for some pZ
(b,c)R(bc) is divisible by n.
bc=nq forsome qZ
therefore,(a,b)R and bcR
ab=npbc=nq
(ab)+(bc)=np+nq
ac=n(p+q)
acisdivisiblebyn$.
(ac)R
Thus, (a,b)R and (b,c)R
(a,c)R for all a,b,cZ
So, R is transitive relation on Z.
Thus, R being reflexive, symmetric and transitive, is an equivalence relation

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