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Question

Let n be a fixed positive integer. Let a relation R be defined in Z (the set of all integers) as follows: aRb, if (a−b)n, that is, if a−b is divisible by n. Then the relation R, is

A
Reflexive only
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B
Symmetric only
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C
Transitive only
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D
An equivalence relation
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Solution

The correct option is D An equivalence relation
R is reflexive as for any integer a we have aa=0 divisible by n. Hence aRa for all aZ
If R is symmetric, let aRb. Then by definition of R, ab=nk where kZ and ba=kn where kZ and so bRa.
Thus we have, ab=k1n,bc=k2n where k1k2Z. then it follows that (ac)=(ab)+(bc)=k1n+k2n=n(k1+k2) where k1+k2Z

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