Let n be a fixed positive integer. Let a relation R be defined in Z (the set of all integers) as follows: aRb, if (a−b)n, that is, if a−b is divisible by n. Then the relation R, is
A
Reflexive only
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B
Symmetric only
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C
Transitive only
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D
An equivalence relation
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Solution
The correct option is D An equivalence relation R is reflexive as for any integer a we have a−a=0 divisible by n. Hence aRa for all a∈Z
If R is symmetric, let aRb. Then by definition of R, a−b=nk where k∈Z and b−a=−kn where −k∈Z and so bRa.
Thus we have, a−b=k1n,b−c=k2n where k1∈k2Z. then it follows that (a−c)=(a−b)+(b−c)=k1n+k2n=n(k1+k2) where k1+k2∈Z