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Question

Let n be a positive integer. If the coefficients of 2nd,3rd and 4th terms in the expansion of (1+x)n are in A.P., then the value of n is .......

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Solution

Let, the coefficients of 2nd,3rd and 4th terms in the
expansion of (1+x)n is nC1,nC2,nC3.
According to given condition
2(nC2)=nC1+nC3
2n(n1)1.2=n+n(n1)(n2)1.2.3
n1=1+(n1)(n2)6
n1=1+n23n+26
6n6=6+n23n+2n209n+14=0
(n2)(n7)=0n=2 or n=7
But nC3 is true for n3, therefore n=7 is the answer

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