Let N be least positive integer such that whenever a non-zero digit c is written after the last digit of N, the resulting number is divisible by c. The sum of the digits of N is
A
9
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B
18
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C
27
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D
36
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Solution
The correct option is A9 N is least positive integer and when a digit c is written after last digit of N, the resulting number is divisible by c.
⇒So, (N)cc
Least positive integer (N) which is divisible by digit c i.e. (1−9)
So possible number is
⇒(9×8×7×5)cc
Number, 9×8×7×5 is divisible by all the digits from 1 to 9