Let N be the greatest number that will divide $1305, 4665 a n d 6905$ leaving the same remainder in each case. The sum of the digits of N is

4

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5

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6

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8

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Solution

The correct option is A $4$
Similar to Q. No. 3
$4665 - 1305 = 3360, 6905 - 4665 = 2240,$
$6905 - 1305 = 5600$
Required number (N) = HCF of 3360, 2240 and 5600
$\Rightarrow N = 1120$
$\Rightarrow$ Sum of digits of $N = 1 + 1 + 2 + 0 = 4$

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