Question

Let N be the set of natural numbers, Define a real valued function
$f:N\to N$ by $f\left(x\right)=2x+1$.
Using this definition, complete the table given below.

x	1	2	3	4	5	6	7
y	f(1)=	f(2)=	f(3)=	f(4)=	f(5)=	f(6)=	f(7)=

Answer 1

Given ; $f:N\to N$
$f\left(x\right)=2x+1$ ...(1)
Evaluate value of the function
Put $x=1$ im equation (1), we get
$\Rightarrow f\left(1\right)=2.1+1=3\Rightarrow f\left(1\right)=3$
Put x=2 in equation (1), we get
$\Rightarrow f\left(2\right)=2.2+1=4+1=5\Rightarrow f\left(2\right)=5$
Put x=3 in equation (1), we get
$\Rightarrow f\left(3\right)=2.3+1=6+1=7\Rightarrow f\left(3\right)=7$
Put x=4 in equation (1), we get
$\Rightarrow f\left(5\right)=2.4+1=8+1=9\Rightarrow f\left(4\right)=9$
Put x=5 in equation (1), we get
$\Rightarrow f\left(5\right)=2.5+1=10+1=11\Rightarrow f\left(5\right)=11$
Put x =6 in equation (1), we get
$\Rightarrow f\left(6\right)=2.6+1=12+1=13\Rightarrow f\left(6\right)=13$
Put x =7 in equation (1), we get
$\Rightarrow f\left(7\right)=2.7+1=14+1=15\Rightarrow f\left(7\right)=15$
Complete table is:

x	1	2	3	4	5	6	7
y	f(1)=3	f(2)=5	f(3)=7	f(4)=9	f(5)=11	f(6)=13	f(7)=15