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Question

Let N denote the set of all natural numbers and R be the relation on NxN defined by (a,b)R(c,d)ad(b+c)=bc(a+d), them R is

A
reflexive only
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B
symmetric only
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C
transitive only
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D
equivalence
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Solution

The correct option is D equivalence
For Reflexive
(a,b)Nab=baN(a,b)R(a,b)RisReflexive
Symmetric
(a,b)R(c,d)ad=bcbc=adcb=adcb=da(c,d)R(a,b)So,RisSymmetric
For Transitive
If(a,b)R(c,d)(c,d)R(e,f)ad=bccf=deab=cd(i)cd=ef(ii)compareequation(i)and(ii)ab=efaf=ebaf=be(a,b)R(e,f)So,RisTransitive
So, Relation of R is equivalence.

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