The correct option is B Range of R2 is {1,2,3,4}.
R1={(1,8),(2,6),(3,4),(4,2)}R2={(8,1),(6,2),(4,3),(2,4)}Range of R2={1,2,3,4}
(1,8)∈R1 but (8,1)∉R1, so R1 is not symmetric.
(4,2)∈R1 & (2,6)∈R1 but (4,6)∉R1, So R1 is not transitive.
Similarly, R2 is neither symmetric nor transitive.