Let N - 22- 33- 74How many factors of number N are in the form 4k - 1- k - N

The correct option is B 9 For number of form 4K+1 it must be of form 3^b×7^c with b+c as even.Way of choosing b and c = ...

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Properties of Iota

Let N = 22×...

Question

Let N = $2^{2} \times 3^{3} \times 7^{4}$
How many factors of number N are in the form 4k + 1, $(k ϵ N)$

9

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Solution

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Similar questions

2^{2} \times 3^{3} \times 7^{4}

N

54

2^{2} \times 3^{3} \times 7^{4}

N^{2}

N = 2^{5} \times 3^{7} \times 9^{2} \times 11^{4} \times 13^{3}

N = 2^{3} \times 3^{2} \times 5^{3} \times 10.

2 P + 1

A = {9, 10, 11, 12, 13}

f : A \to N

f (n) =

n

f

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