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Question

Let n_K be the number of real solutions of the equation \vert x+1\vert+\vert x-3\vert=K, then (1) n_K=0, if K<4 (2) n_K=2, if K>4 (3) n_K is infinitely many if K=4 (4) Minimum value of f(x)=\vert x+1\vert+\vert x-3\vert is 2

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Solution

99996184146-0-0

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