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Question

Let np and ne the number of holes and conduction electrons in an intrinsic semiconductor. Then:

A
np>ne
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B
np=ne
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C
np<ne
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D
npne
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Solution

The correct option is B np=ne
In an intrinsic semicondutor, number of holes carriers are equal to number of electrons as no doping is there in intrinsic material.
In extrinsic materials, due to doping, numbers of holes are different to those of electrons.
So,
np=ne

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