Question

Let $n\left(s\right)$ denotes number of solutions of the equation $|x^2-2x-3|=k$. For $k>4$, the value of $n\left(s\right)$ equals

• A. $0$
• B. $2$
• C. $3$
• D. $4$

Answer 1

The correct option is B $2$

$x^2-2x-3=0$

$\Rightarrow (x+1)(x-3)=0$

$\therefore x=-1$, $x=3$

$|x^2-2x-3|=k$

Hence, here are two solution.