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Linear Functions

Let N = sin x...

Question

Let N = sin x + cos(/3 -x). Cos(/3+x) then the value of log to the base 2

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{log}_{10} sin x + {log}_{10} cos x = - 1

{log}_{10} (sin x + cos x) = \frac{({log}_{10} n - 1)}{2}

then the value of 'n/3' is

{log}_{10} sin x + {log}_{10} cos x = - 1

{log}_{10} (sin x + cos x) = \frac{{log}_{10} n - 1}{2}

, then the value of

\frac{n}{3}

{log}_{10} sin x + {log}_{10} cos x = - 1

{log}_{10} (sin x + cos x) = \frac{({log}_{10} n) - 1}{2},

then the value of

n

0 < x < \frac{π}{2}

cos x = \frac{3}{\sqrt{10}}

, then the value of

{log}_{10} sin x + {log}_{10} cos x + {log}_{10} tan x

{log}_{10} sin x + {log}_{10} cos x = - 1, x \in (0, \frac{π}{2})

{log}_{10} (sin x + cos x) = \frac{({log}_{10} n) - 1}{2},

then the value of

n

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