Let nU - 700- nA - 200- nB - 300 and nA - B - 100- then nAc - Bc is -

N(A^c ∩ B^c) = n((A ∪ B)^c) nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; = n(∪ ) n(A ∪ B) nbsp; nbsp; nbs ...

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De Morgan's Laws

Let nU = 700,...

Question

Let $n (U) = 700$ , $n (A) = 200$ , $n (B) = 300$ and $n (A \cap B) = 100, then n (A^{c} \cap B^{c})$ is -

400

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600

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300

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200

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Solution

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Similar questions

n (U) = 700

n (A) = 200

n (B) = 300

n (A \cap B) = 100, then n (A^{c} \cap B^{c})

n (U) = 700, n (A) = 200, n (B) = 300

n (A \cap B) = 100

n (A^{c} \cap B^{c}) =

n (U) = 700, n (A) = 200, n (B) = 300

n (A \cap B) = 100

n (A^{c} \cap B^{c})

Let n(U) = 700, n(A) = 200, n(B) = 300 and n(A ∩ B) = 100,

Then n $(A^{c} \cap B^{c})$ =

n (U) = 700

n (A) = 200

n (B) = 300

n (A \cap B) = 100, then n (A^{c} \cap B^{c})

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