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De Morgan's Law

Let nU = 700,...

Question

Let $n (U) = 700$ , $n (A) = 200$ , $n (B) = 300$ and $n (A \cap B) = 100$ , Then $n (A^{C} \cap B^{C}) =$

A

100

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B

300

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C

500

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D

450

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Solution

The correct option is B $300$
$n (A^{C} \cap B^{C}) = n ((A \cup B)^{C}) = n (U) - n (A \cup B)$
$= 700 - [200 + 300 - 100]$
$= 300$

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Similar questions

n (U) = 700

n (A) = 200

n (B) = 300

n (A \cap B) = 100

n (A^{C} \cap B^{C}) =

n (U) = 700, n (A) = 200, n (B) = 300

n (A \cap B) = 100

n (A^{c} \cap B^{c}) =

n (U) = 700, n (A) = 200, n (B) = 300

n (A \cap B) = 100

n (A^{c} \cap B^{c})

Let n(U) = 700, n(A) = 200, n(B) = 300 and n(A ∩ B) = 100,

Then n $(A^{c} \cap B^{c})$ =

n (U) = 700

n (A) = 200

n (B) = 300

n (A \cap B) = 100, then n (A^{c} \cap B^{c})

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