Let normal's drawn to parabola at point's P(0,0) and Q(3,−1) intersect at (2,1). If PQ is bisected by the axis of the parabola, then
A
Equation of directrix is x+3y+5=0
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B
Slope of axis is 3
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C
Focus is (8,0)
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D
Slope of tangent at vertex is 13
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Solution
The correct options are A Equation of directrix is x+3y+5=0 B Slope of axis is 3 Clearly normals are perpendicular to each other. So, quadrilateral formed by tangents and normals at given points here forms a rectangle. ∵ axis of the parabola bisects the PQ and tangents drawn to the ends of the chord are perpendicular ∴PQ is the latusrectum of the given parabola whose focus is (32,−12). Hence tangents will intersect at (1,−2)
∵ directrix is parallel to latusrectum ∴ Slope of directrix =slope of tangent at vertex=−13 and Slope of axis =3 So, equation of directrix is y+2=−13(x−1) ⇒x+3y+5=0