Question

Let O(0,0),P(3,4),Q(6,0) be the verticals of triangle OPQ .The point R inside the triangle OPQ is such that the triangles OPR, PQR, OQR are of equal area. The point S is such that OS = PS = QS.Then RS =

• A.
• B.
• C.
• D.

Answer 1

The correct option is D

R is centroid .S is circumcentre . $R=(3,\frac{4}{3}),S=(3,\frac{7}{8})$
RS = $\frac{11}{24}$