Let ‘O’ be the centre of ellipse for which A,B are end points of major axis and C,D are end points of minor axis, F is focus of the ellipse. If in radius of ΔOCF is '1' then |AB|×|CD|=
A
65
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B
52
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C
78
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D
47
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Solution
The correct option is A 65 r=ΔS⇒Δ=S12(ae)b=ae+b+√a2e2+b22ae=6⇒6b=6+b+√36+b2⇒b=52⇒a2(1−e2)=254⇒a2−36=254⇒a=132 Hence |AB|×|CD|= 2a x 2b =65