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Question

Let ‘O’ be the centre of ellipse for which A,B are end points of major axis and C,D are end points of minor axis, F is focus of the ellipse. If in radius of ΔOCF is '1' then |AB|×|CD|=

A
65
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B
52
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C
78
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D
47
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Solution

The correct option is A 65
r=ΔSΔ=S12(ae)b=ae+b+a2e2+b22ae=66b=6+b+36+b2b=52a2(1e2)=254a236=254a=132
Hence |AB|×|CD|= 2a x 2b =65

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