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Question

Let O be the origin, and OX,OY,OZ be three unit vectors in the directions of the sides QR,RP,PQ, respectively, of a triangle PQR.

|OX×OY|=

A
sin(P+Q)
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B
sin2R
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C
sin(P+R)
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D
sin(Q+R)
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Solution

The correct option is A sin(P+Q)
|OX×OY|=|OX||OY|sin(R)=sin(πR)=sin(P+Q)

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