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Standard XIII

Mathematics

Cross Product

Let O be the ...

Question

Let O be the origin and OX, OY, OZ be three unit vectors in the directions of the sides QR, RP, PQ respectively, of a triangle PQR.
$| O X \times O Y | =$

sin (P+Q)

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sin (Q + R)

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sin (P + R)

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sin 2R

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Solution

The correct option is A
sin (P+Q)

$sin R = sin (P + Q)$

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Similar questions

Q. Let

O

be the origin, and

- - \to O X, - - \to O Y, - - \to O Z

be three unit vectors in the directions of the sides

- - \to Q R, - - \to R P, - - \to P Q,

respectively, of a triangle

P Q R .

| - - \to O X \times - - \to O Y | =

Let O be the origin and OX, OY, OZ be three unit vectors in the directions of the sides QR, RP, PQ respectively, of a triangle PQR.
If the triangle PQR varies, then the minimum value of $cos (P + Q) + cos (Q + R) + cos (R + P)$ is

Q. Let

O

be the origin, and

- - \to O X, - - \to O Y, - - \to O Z

be three unit vectors in the directions of the sides

- - \to Q R, - - \to R P, - - \to P Q,

respectively, of a triangle

P Q R .

If the triangle

P Q R

varies, then the minimum value of

cos (P + Q) + cos (Q + R) + cos (R + P)

Q. Let

O

be the origin, and

- - \to O X, - - \to O Y, - - \to O Z

be three unit vectors in the directions of the sides

- - \to Q R, - - \to R P, - - \to P Q,

respectively, of a triangle

P Q R .

If the triangle

P Q R

varies, then the minimum value of

cos (P + Q) + cos (Q + R) + cos (R + P)

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Let O be the origin and OX, OY, OZ be three unit vectors in the directions of the sides QR, RP, PQ respectively, of a triangle PQR. |OX×OY|=

The correct option is A sin (P+Q) sin R=sin(P+Q)

Let O be the origin and OX, OY, OZ be three unit vectors in the directions of the sides QR, RP, PQ respectively, of a triangle PQR.
$| O X \times O Y | =$

The correct option is A
sin (P+Q)

$sin R = sin (P + Q)$