Let $O$ be the origin and $P$ be the point at a distance $3$ units from origin. If d.x.s' of OP are 1, - 2, - 2, then coordinates of P is given by

1, - 2, - 2

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3, - 6, - 6

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\frac{1}{3}, - \frac{2}{3}, - \frac{2}{3}

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\frac{1}{9}, - \frac{2}{9}, - \frac{2}{9}

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Solution

The correct option is A $1, - 2, - 2$
$r = 3$ ,directions $(l, m, n) = (\frac{1}{3}, \frac{- 2}{3}, \frac{- 2}{3})$
$∴$ $P (x, y, z)$ be coordinates of point .
$t h e r e f o r e (x - 0) = \frac{1}{3} \times 3, y - 0 = \frac{- 2}{3} \times 3, z - 0 = \frac{- 2}{3} \times 3 (x, y, z) = (1, - 2, - 2)$

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Let O be the origin and P be the point at a distance 3 units from origin. If d.x.s' of OP are 1, - 2, - 2, then coordinates of P is given by

The correct option is A 1,−2,−2r=3,directions (l,m,n)=(13,−23,−23)∴ P(x,y,z) be coordinates of point .therefore(x−0)=13×3,y−0=−23×3,z−0=−23×3(x,y,z)=(1,−2,−2)

Let $O$ be the origin and $P$ be the point at a distance $3$ units from origin. If d.x.s' of OP are 1, - 2, - 2, then coordinates of P is given by