Let $O =$ Set of odd natural numbers $= {1, 3, 5, 7, 9, . . .}$ and $E =$ Set of even natural numbers $= {2, 4, 6, 8, 10, . . . . . . . .}$ . Show that $2 \in E$ .

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Solution

$O = {1, 3, 5, 7, 9, . . . . .}$
$E = {2, 4, 6, 8, 10, . . . . .}$
So it is clear from the definition of $E$ , $2 \in E$

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