You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Mathematics

Perpendicular from the Centre of a Circle to a Chord

Let OM and ON...

Question

Let OM and ON be perpendiculars drawn from the centre O of a circle to chords AB and CD respectively. If AB= 10 cm, then CD= .

10 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.5 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7.5 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 10 cm

From figure, it is clear that $O M ⊥ A B, O N ⊥ C D$ and OM=ON.
We know the property that the chords equidistant from the centre of a circle are equal in length.
$⟹ A B = C D$
Thus, $C D = 10 cm .$

Suggest Corrections

Similar questions

In the given figure, BOC is a diameter of a circle with centre O. If AB and CD are two chords such that AB||CD and AB = 10 cm then CD = ?

(a) 5 cm

(b) 12.5 cm

(d) 10 cm

Q. Let OM and ON be perpendiculars drawn from the centre O of a circle to chords AB and CD respectively. If AB= 10 cm, then CD= .

Q. In the figure given,

O

is the centre of the circle.

A B

and

C D

are two chords of the circle.

O M

is perpendicular to

C D

and

O N

is perpendicular to

A B

A B = 24 c m, O N = 5 c m, O M = 12 c m

. Find the length of chord

C D

O

is the centre of the circle.

A B

and

C D

are two chords of the circle.

O M ⊥ A B

and

O N ⊥ C D

. If

O M = O N = 3

cm and

A M = B M = 4.5

cm, then

C D

is equal to

Q. In the given figure,

O

is the centre of the circle.

A B

and

C D

are two chords of the circle.

O M

is perpendicular to

A B

and

O N

is perpendicular to

C D

A B = 24 c m, O M = 5 c m, O N = 12 c m

. Find the:
(i) radius of the circle.
(ii) length of chord

C D

Join BYJU'S Learning Program

Let OM and ON be perpendiculars drawn from the centre O of a circle to chords AB and CD respectively. If AB= 10 cm, then CD= .

The correct option is A 10 cm From figure, it is clear that OM⊥AB,ON⊥CD and OM=ON. We know the property that the chords equidistant from the centre of a circle are equal in length. ⟹AB=CD Thus, CD=10 cm.

The correct option is A 10 cm

From figure, it is clear that $O M ⊥ A B, O N ⊥ C D$ and OM=ON.
We know the property that the chords equidistant from the centre of a circle are equal in length.
$⟹ A B = C D$
Thus, $C D = 10 cm .$